Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 10: 30

Answer

$w^6-4$

Work Step by Step

We know that $f(x)=x^2-4$ and $g(x)=x^3$, so: $f(g(w))=f(w^3)=(w^3)^2-4=w^6-4$
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