Answer
The function is odd.
Work Step by Step
We have that $E(-x)=E(x)$ and $O(-x)=-O(x)$.
Let $\Phi=O\circ O$ Then
$$\Phi(-x)=O\circ O(-x)=O(O(-x))=O(-O(x))=-O(O(x))=-O\circ O(x)=-\Phi(x)$$
which means that the function is odd.
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 12: 100
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