Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.2 Representing Functions - 1.2 Exercises - Page 22: 37

Answer

\[s\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {1\,\,\,\,\,\,\,\,{\text{if}}\,\,\,x\, < 0} \\ { - \frac{1}{2}\,\,\,\,{\text{if}}\,\,\,\,x > 0} \end{array}} \right.\]

Work Step by Step

$$\eqalign{ & {\text{Calculate the slope for the intervals }}x < 0{\text{ and }}x > 0 \cr & \cr & {\text{For }}x < 0{\text{ we can use the points }}\left( { - 3,0} \right){\text{ and }}\left( {0,3} \right), \cr & {\text{then}} \cr & m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \frac{{3 - 0}}{{0 - \left( { - 3} \right)}} \cr & m = \frac{3}{3} = 1 \cr & \cr & {\text{For }}x > 0{\text{ we can use the points }}\left( {0,3} \right){\text{ and }}\left( {2,2} \right), \cr & m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \frac{{2 - 3}}{{2 - 0}} \cr & m = - \frac{1}{2} \cr & \cr & {\text{Therefore,}} \cr} $$ \[s\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {1\,\,\,\,\,\,\,\,{\text{if}}\,\,\,x\, < 0} \\ { - \frac{1}{2}\,\,\,\,{\text{if}}\,\,\,\,x > 0} \end{array}} \right.\]
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