Answer
( please see image)
Work Step by Step
The x-intercept (y=0) is 0,
the y intercept (x=0) is 0,
so we have one point on the line, (0,0)
We need another point. Let x=$5$.
Then,
$3(5)-5y=0\qquad/-15$
$-5y=-15 \qquad/\div(-5)$
$y=3$
Another point on the line is ($5,3$)
Plot the two points and draw a line through them.
( please see image)
