Answer
$D = (-\infty, -3)\cup(3,+\infty)$
Work Step by Step
The domain of $f(x) = \log (x^{2} -9) $ consists of all x for which $x^{2} -9\gt 0$
Solving the inequality for x we have $x \lt -3$ or $x \gt 3$
$D = (-\infty, -3)\cup(3,+\infty)$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 99: 70
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