Answer
There are two errors in the calculation
Work Step by Step
The given calculation was wrong since $2\log(x+2)$ cannot be equal to $2(\log x+\log2)$. The following calculation should be just like this: $(\log(x+2)^{2})=2\log(x+2)$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 99: 72
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