Answer
$(2a-4b)^{2}=4a^{2}-16ab+16b^{2}$
Work Step by Step
$(2a-4b)^{2}$
Rewrite this expression as $(2a-4b)(2a-4b)$ and evaluate the product:
$(2a-4b)^{2}=(2a-4b)(2a-4b)=...$
$...=4a^{2}-8ab-8ab+16b^{2}=4a^{2}-16ab+16b^{2}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.1 Polynomials - R.1 Exercises - Page R-5: 24
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