Answer
$-6(2q^{2}+4q-3)+4(-q^{2}+7q-3)=-16q^{2}+4q+6$
Work Step by Step
$-6(2q^{2}+4q-3)+4(-q^{2}+7q-3)$
Multiply $-6$ and $4$ by each term inside its respective parentheses and then simplify by combining like terms:
$(-12q^{2}-24q+18)+(-4q^{2}+28q-12)=-16q^{2}+4q+6$