Answer
$\dfrac{8}{9}$
Work Step by Step
Simplify by factoring the numerator and the denominator then cancelling common factors to have:
$\require{cancel}
\\=\dfrac{8(k+2)}{9(k+2)}
\\=\dfrac{8\cancel{(k+2)}}{9\cancel{(k+2)}}
\\=\dfrac{8}{9}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.3 Rational Expressions - R.3 Exercises - Page R-10: 3
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