Answer
$\dfrac{m-2}{m+3}$
Work Step by Step
Simplify by factoring the numerator and the denominator then cancelling common factors to have:
$\require{cancel}
\\=\dfrac{(m-2)(m-2)}{(m+3)(m-2)}
\\=\dfrac{\cancel{(m-2)}(m-2)}{(m+3)\cancel{(m-2)}}
\\=\dfrac{m-2}{m+3}$
