Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.2 - Combining Functions; Shifting and Scaling Graphs - Exercises 1.2 - Page 20: 55

Answer

(a) D: $[0,2]$, R: $[2,3]$ (b) D: $[0,2]$, R: $[-1,0]$ (c) D: $[0,2]$, R: $[0,2]$ (d) D: $[0,2]$, R: $[-1,0]$ (e) D: $[-2,0]$, R: $[0,1]$ (f) D: $[1,3]$, R: $[0,1]$ (g) D: $[-2,0]$, R: $[0,1]$ (h) D: $[-1,1]$, R: $[0,1]$

Work Step by Step

See the graph. The original domain is $[0,2]$ and the range is $[0,1]$. Shift the domain for range according to the operations on the function: (a) For $f(x)+2$, the new domain is $[0,2]$ and the new range is $[2,3]$ (b) For $f(x)-1$, the new domain is $[0,2]$ and the new range is $[-1,0]$ (c) For $2f(x)$, the new domain is $[0,2]$ and the new range is $[0,2]$ (d) For $-f(x)$, the new domain is $[0,2]$ and the new range is $[-1,0]$ (e) For $f(x+2)$, the new domain is $[-2,0]$ and the new range is $[0,1]$ (f) For $f(x-1)$, the new domain is $[1,3]$ and the new range is $[0,1]$ (g) For $f(-x)$, the new domain is $[-2,0]$ and the new range is $[0,1]$ (h) For $-f(x+1)+1$, the new domain is $[-1,1]$ and the new range is $[0,1]$
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