Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.2 - Combining Functions; Shifting and Scaling Graphs - Exercises 1.2 - Page 20: 56

Answer

(a) D: $[0,4]$, R: $[-3,0]$. (b) D: $[-4,0]$, R: $[0,3]$. (c) D: $[-4,0]$, R: $[0,3]$. (d) D: $[-4,0]$, R: $[1,4]$. (e) D: $[2,6]$, R: $[-3,0]$. (f) D: $[-2,2]$, R: $[-3,0]$. (g) D: $[1,5]$, R: $[-3,0]$. (h) D: $[0,4]$, R: $0,3]$.

Work Step by Step

See the graph. The original domain is $[-4,0]$ and the range is $[-3,0]$. Shift the domain and range according to the operations on the function: (a) For $g(-t)$, the new domain is $[0,4]$ and the new range is $[-3,0]$. (b) For $-g(t)$, the new domain is $[-4,0]$ and the new range is $[0,3]$. (c) For $g(t)+3$, the new domain is $[-4,0]$ and the new range is $[0,3]$. (d) For $1-g(t)$, the new domain is $[-4,0]$ and the new range is $[1,4]$. (e) For $g(-t+2)$, the new domain is $[2,6]$ and the new range is $[-3,0]$. (f) For $g(t-2)$, the new domain is $[-2,2]$ and the new range is $[-3,0]$. (g) For $g(1-t)$, the new domain is $[1,5]$ and the new range is $[-3,0]$. (h) For $-g(t-4)$, the new domain is $[0,4]$ and the new range is $0,3]$.
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