Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 29: 63

Answer

1.46

Work Step by Step

We first calculate the third angle $ C=\pi-A-B=\pi-\frac{\pi}{4}-\frac{\pi}{3}=\frac{5\pi}{12}$ Next we use the law of sines $\frac{a}{sinA}=\frac{c}{sinC}$, which leads to $ a=\frac{c\cdot sinA}{sinC}=\frac{2sin\pi/4}{sin5\pi/12}=1.46$
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