Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 28: 62

Answer

$\frac{3\sqrt {21}}{14}$

Work Step by Step

From exercise 59, we know that $ c=\sqrt 7$. Using the law of sines, we have $\frac{SinB}{b}=\frac{sinC}{c}$ Plug-in the numbers: $ sinB=\frac{3sin60^\circ}{\sqrt 7}=\frac{3\sqrt {21}}{14}$
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