Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 28: 39

Answer

$-\cos{x}$

Work Step by Step

Addition formula $$\cos{(A+B)}= \cos{A} \cos{B}-\sin{A}\sin{B}$$ $\therefore \cos{(\pi+x)} = \cos{\pi} \cos{x} - \sin{\pi} \sin{x}$ $\cos{(\pi+x)} = (-1) \times \cos{x} - (0) \times \sin{x}$ $\cos{(\pi+x)} = -\cos{x}$
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