Answer
$$2^{\sqrt3}\times7^{\sqrt3}=14^{\sqrt3}$$
Work Step by Step
$$2^{\sqrt3}\times7^{\sqrt3}$$
As $2\gt0$ and $7\gt0$, we can apply the law of exponents here.
Applying this law: $$a^x\times b^x=(ab)^x$$ we have
$$2^{\sqrt3}\times7^{\sqrt3}=(2\times7)^{\sqrt3}=14^\sqrt3$$