Answer
The conclusion is: $\therefore$ 0 is even.
Work Step by Step
Universal modus ponens:
$\forall x$, if $P(x)$ then $Q(x).$
$P(a)$ for a particular $a$.
$\therefore Q(a)$.
In this case P(x) is: If an integer x equals $2\cdot k$ and k is an integer.
Q(x) is: x is even.
a is 0 and k is 0.
The conclusion Q(a) is: 0 is even.
