Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.9 Interval Notation; Solving Inequalities - A.9 Assess Your Understanding - Page A79: 25

Answer

$\text{(a)}\quad$ $2x+4\lt 5$. $\text{(b)}\quad$ $2x-4\lt-3$. $\text{(c)}\quad$ $ 6x+3\lt 6$. $\text{(d)}\quad$ $-4x-2\gt -4$.

Work Step by Step

The given inequality is $\Rightarrow 2x+1\lt 2$ (a) Add $3$ to each side. $\Rightarrow 2x+1+3\lt 2+3$ Simplify. $\Rightarrow 2x+4\lt 5$ (b) Subtract $5$ from each side. $\Rightarrow 2x+1-5\lt 2-5$ Simplify. $\Rightarrow 2x-4\lt-3$ (c) Multiply each side by $3$. $\Rightarrow 3\cdot (2x+1)\lt 3\cdot (2)$ Use distributive property. $\Rightarrow 6x+3\lt 6$. (d) Multiply each side by $-2$ and change the direction of the inequality. $\Rightarrow -2\cdot (2x+1)\gt -2\cdot (2)$ Use distributive property. $\Rightarrow -4x-2\gt -4$.
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