Answer
Set notation:$\quad \{x|x\geq12\}$
Interval notation:$\quad[12,\infty )$.
The graph is shown below.
Work Step by Step
Multiply both sides by $6$.
$6\cdot \frac{x}{3} \geq 6\cdot (2+ \frac{x}{6}) $
Simplify.
$2x \geq 12+ x $
Subtract $x$ from both sides.
$2x-x \geq 12+ x-x $
Simplify.
$x \geq 12$
The solution set is $\{x|x\geq 12\}$
or interval notation is $[12,\infty)$.
To graph, use an open bracket at $12$ and shade the region to its right.
