Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.3 Lines - 1.3 Assess Your Understanding - Page 31: 106

Answer

$\text{ perpendicular}$

Work Step by Step

Step 1. Find the slopes of each line: for $y=\frac{1}{2}x-3$, we have $m_1=\frac{1}{2}$; $y=-2x+4$, we have $m_2=-2$; Step 2. Since $m_1\cdot m_2=-1$, the two lines are perpendicular.
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