Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.3 Lines - 1.3 Assess Your Understanding - Page 31: 49

Answer

$y=-\frac{2}{3}x-\frac{1}{3}$

Work Step by Step

We know that if the slope of a line is $m$ and it contains $P_1(x_1,y_1)$, then its equation is: $y-y_1=m(x-x_1).$ Hence, here we have $y-(-1)=-\frac{2}{3}(x-1)\\ y+1=-\frac{2}{3}x+\frac{2}{3}\\ y=-\frac{2}{3}x+\frac{2}{3}-1\\ y=-\frac{2}{3}x-\frac{1}{3}$
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