Answer
$\sqrt{3}+\sqrt[3]{15}$
Work Step by Step
The radicand of $\sqrt[3]{15}$ has no perfect cube factor. This means that the radical is already in its simplest form.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 46: 82
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