Answer
$x^3-3x^2+3x-1$
Work Step by Step
RECALL:
$(a-b)^3=a^3-3a^2b+ 3ab^2-b^3$
Use the formula above with $a=x$ and $b=1$ to obtain:
$=x^3-3(x)^2(1)+3(x)(1^2)-1^3
\\=x^3-3x^2(1)+3x(1)-1
\\=x^3-3x^2+3x-1$
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