Answer
$4x^2-28x+49$
Work Step by Step
Assuming $x\ne\frac{7}{2}$, we have
$\frac{(2x-7)^5}{(2x-7)^3}=(2x-7)^2=4x^2-28x+49$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.4 - Polynomials - Exercise Set - Page 56: 89
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