Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Chapter 11 Test Prep - Review Exercises - Page 1081: 10

Answer

$$6,12,24,48,96$$

Work Step by Step

$$\eqalign{ & {\text{geometric;}}\,\,\,{a_1} = 6,\,\,r = 2 \cr & \cr & {\text{The }}n{\text{th term is }}{a_n} = {a_1}{r^{n - 1}} \cr & {a_n} = 6{\left( 2 \right)^{n - 1}} \cr & {\text{Find }}{a_2},\,\,{a_3},{a_4},{a_5} \cr & {a_2} = 6{\left( 2 \right)^{2 - 1}} = 12 \cr & {a_3} = 6{\left( 2 \right)^{3 - 1}} = 24 \cr & {a_4} = 6{\left( 2 \right)^{4 - 1}} = 48 \cr & {a_{52}} = 6{\left( 2 \right)^{5 - 1}} = 96 \cr & \cr & {\text{The terms are:}} \cr & 6,12,24,48,96 \cr} $$
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