Answer
$$ - 5, - 1, - \frac{1}{5}, - \frac{1}{{25}}, - \frac{1}{{125}}$$
Work Step by Step
$$\eqalign{
& {\text{geometric;}}\,\,\,{a_1} = - 5,\,\,{a_2} = - 1 \cr
& \cr
& r = \frac{{{a_2}}}{{{a_1}}} = \frac{{ - 1}}{{ - 5}} = \frac{1}{5} \cr
& {\text{The }}n{\text{th term is }}{a_n} = {a_1}{r^{n - 1}} \cr
& {a_n} = - 5{\left( {\frac{1}{5}} \right)^{n - 1}} \cr
& {\text{Find }}{a_3},{a_4},{a_5} \cr
& {a_3} = - 5{\left( {\frac{1}{5}} \right)^{3 - 1}} = - \frac{1}{5} \cr
& {a_4} = - 5{\left( {\frac{1}{5}} \right)^{4 - 1}} = - \frac{1}{{25}} \cr
& {a_{52}} = - 5{\left( {\frac{1}{5}} \right)^{5 - 1}} = - \frac{1}{{125}} \cr
& \cr
& {\text{The terms are:}} \cr
& - 5, - 1, - \frac{1}{5}, - \frac{1}{{25}}, - \frac{1}{{125}} \cr} $$
