Answer
56
Work Step by Step
$$\eqalign{
& C\left( {8,3} \right) \cr
& {\text{Use the combination formula }}C\left( {n,r} \right) = \frac{{n!}}{{\left( {n - r} \right)!r!}} \cr
& {\text{ }}C\left( {8,3} \right) = \frac{{8!}}{{\left( {8 - 3} \right)!3!}} \cr
& {\text{Evaluate and simplify}} \cr
& {\text{ }}C\left( {8,3} \right) = \frac{{8!}}{{5!3!}} \cr
& {\text{ }}C\left( {8,3} \right) = \frac{{5! \cdot 8 \cdot 7 \cdot 6}}{{5!3!}} \cr
& {\text{ }}C\left( {8,3} \right) = 56 \cr} $$
