Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Chapter 11 Test Prep - Review Exercises - Page 1083: 59

Answer

$$252$$

Work Step by Step

$$\eqalign{ & C\left( {10,5} \right) \cr & {\text{Use the combination formula }}C\left( {n,r} \right) = \frac{{n!}}{{\left( {n - r} \right)!r!}} \cr & {\text{ }}C\left( {10,5} \right) = \frac{{10!}}{{\left( {10 - 5} \right)!5!}} \cr & {\text{Evaluate and simplify}} \cr & {\text{ }}C\left( {10,5} \right) = \frac{{10!}}{{5!5!}} \cr & {\text{ }}C\left( {10,5} \right) = \frac{{5! \cdot 6 \cdot 7 \cdot 8 \cdot 9 \cdot 10}}{{5!\left( {1 \cdot 2 \cdot 3 \cdot 4 \cdot 5} \right)}} \cr & {\text{ }}C\left( {10,5} \right) = \frac{{6 \cdot 7 \cdot 8 \cdot 9 \cdot 10}}{{1 \cdot 2 \cdot 3 \cdot 4 \cdot 5}} \cr & {\text{ }}C\left( {10,5} \right) = 7 \cdot 2 \cdot 9 \cdot 2 \cr & {\text{ }}C\left( {10,5} \right) = 252 \cr} $$
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