Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 34: 104

Answer

$k^2-5+\frac{2k+10}{k^2+1}$

Work Step by Step

Follow the examples in the book, we have: $\frac{k^4-4k^2+2k+5}{k^2+1}=k^2-5+\frac{2k+10}{k^2+1}$
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