Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 34: 91

$$-14q^{2}+11q-14$$

Initial equation: $-3(4q^{2}-3q+2)+2(-q^{2}+q-4)$ First, distribute the $-3$ to the first set of parenthesis, and the $2$ to the second: $$-12q^{2}+9q-6-2q^{2}+2q-8$$ Then combine like terms to arrive at the final answer: $$-14q^{2}+11q-14$$