Answer
$(x+1)(x^2-x+1)(x-1)(x^2+x^2+1)$
Work Step by Step
Step 1. $x^6-1=(x^3)^2-1=(x^3+1)(x^3-1)$
Step 2. $(x^3+1)(x^3-1)=(x+1)(x^2-x+1)(x-1)(x^2+x^2+1)$
Step 3. Thus $x^6-1=(x+1)(x^2-x+1)(x-1)(x^2+x^2+1)$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 45: 125
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