Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 45: 126

Answer

$(x+1)(x-1)(x^4+x^2+1)$

Work Step by Step

Step 1. $x^6-1=(x^2)^3-1=(x^2-1)(x^4+x^2+1)$ Step 2. $(x^2-1)(x^4+x^2+1)=(x+1)(x-1)(x^4+x^2+1)$ Step 3. Thus $x^6-1=(x+1)(x-1)(x^4+x^2+1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.