Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.10 - Lines - 1.10 Exercises - Page 115: 34

Answer

$y=\dfrac{3}{4}x+6$ or, in general form, $3x-4y+24=0$

Work Step by Step

$x$-intercept $-8;$ $y$-intercept $6$ Use the slope-intercept form of the equation of a line, which is $y=mx+b$, where $m$ is the slope and $b$ is the $y$-intercept of the line. The intercepts of the line are given and these are obviously points through which the line passes. These points are $(-8,0)$ and $(0,6)$. Use them to find the slope of the line: $m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}=\dfrac{6-0}{0-(-8)}=\dfrac{6}{8}=\dfrac{3}{4}$ Substitute $m$ and the $y$-intercept into the formula to obtain the equation of this line: $y=mx+b$ $y=\dfrac{3}{4}x+6$ or, in general form, $3x-4y+24=0$
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