Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.7 - Modeling with Equations - 1.7 Exercises - Page 81: 94

Answer

$x=6$ cubits

Work Step by Step

Assume the length of the reed is $x$ cubits, we are given the following conditions: 1 ninda =12 cubits, so 1 squre nindas =$12^2$ square cubits, area of the field=$375$ sqaure nindas=$375\times12^2$ sqaure cubits, length of the field = $60\times(x-1)$, width of the field =$30x$. The above conditions give the equation $60(x-1)\times30x=375\times12^2$ which lead to a quadratic equation $x^2-x=\frac{375\times12^2}{60\times30}=30$, or $x^2-x-30=0$ As $x$ must be positive, the only solution for the equation is $x=6$ cubits
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