An Introduction to Mathematical Statistics and Its Applications (6th Edition)

Published by Pearson
ISBN 10: 0-13411-421-3
ISBN 13: 978-0-13411-421-7

Chapter 2 Probability - 2.2 Sample Spaces and the Algebra of Sets - Questions - Page 26: 39

Answer

Five hundred respondents said “yes” to the taxes question but “no” to the homeland security question.

Work Step by Step

Let A be the event that the respondents said “yes” to the taxes question. Let B be the event that the respondents said “yes” to the homeland security question. We have given that, \[N(S)=1200\] \[N(A)=600\] \[N(B)=400\] \[N({{A}^{C}}\cap B)=300\] \[\begin{align} & N({{B}^{C}})=N(S)-N(B) \\ & N({{B}^{C}})=1200-400 \\ & N({{B}^{C}})=800 \\ \end{align}\] We have to find the number of respondents said “yes” to the taxes question but “no” to the homeland security question; that means\[N(A\cap {{B}^{C}})\]. We can write \[N(A\cap {{B}^{C}})\]as: \[N(A\cap {{B}^{C}})=N(A)+N({{B}^{C}})-N(A\cup {{B}^{C}})\] We first find \[N(A\cup {{B}^{C}})\], \[\begin{align} & N(A\cup {{B}^{C}})=N(S)-N({{A}^{C}}\cap B) \\ & N(A\cup {{B}^{C}})=1200-300 \\ & N(A\cup {{B}^{C}})=900 \\ \end{align}\] Now we get, \[\begin{align} & N(A\cap {{B}^{C}})=N(A)+N({{B}^{C}})-N(A\cup {{B}^{C}}) \\ & N(A\cap {{B}^{C}})=600+800-900 \\ & N(A\cap {{B}^{C}})=500 \\ \end{align}\] Therefore, five hundred respondents said “yes” to the taxes question but “no” to the homeland security question.
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