Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-4 - Conditional Probability - Exercises - Page 43: 2-100

Answer

a) $\frac{39}{100}$ b) $\frac{20}{100}$ c) $\frac{7}{20}$ d) $\frac{7}{39}$

Work Step by Step

Probability = Total number of favourable outcomes/Total number of possible outcomes a) $P(A)=\frac{7+32}{7+32+13+48}=\frac{39}{100}=0.39$ b) $P(B)=\frac{13+7}{13+7+48+32}=20/100=0.2$ c) $P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{\frac{7}{100}}{\frac{20}{100}}=7/20=0.35$ d) $P(B|A)=\frac{P(B\cap A)}{P(A)}=\frac{\frac{7}{100}}{\frac{39}{100}}=7/39$
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