Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-4 - Conditional Probability - Exercises - Page 43: 2-102

Answer

a) $\frac{82}{100}$ b) $\frac{90}{100}$ c) $\frac{80}{90}$ d) $\frac{80}{82}$

Work Step by Step

Probability = Total number of favourable outcomes/Total number of possible outcomes a) $P(A)=\frac{80+2}{80+2+10+8}=\frac{82}{100}$ b) $P(B)=\frac{80+10}{80+2+10+8}=\frac{90}{100}$ c) $P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{\frac{80}{100}}{\frac{90}{100}}=\frac{80}{90}$ d) $P(B|A)=\frac{P(B\cap A)}{P(A)}=\frac{\frac{80}{100}}{\frac{82}{100}}=\frac{80}{82}$
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