Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-4 - Conditional Probability - Exercises - Page 44: 2-103

Answer

We know that $probability=\frac{\text{number of favorable outcomes}}{\text{number of all outcomes}}$ a) The number of good outcomes is $12$. The number of all outcomes is $12+88=100$ Hence the probability here is: $\frac{12}{100}$ b) The number of good outcomes is $12$. The number of all outcomes is $12+16=28$ Hence the probability here is: $\frac{12}{28}$ c) The number of good outcomes is $34$. The number of all outcomes is $88+34=122$ Hence the probability here is: $\frac{34}{122}$

Work Step by Step

We know that $probability=\frac{\text{number of favorable outcomes}}{\text{number of all outcomes}}$ a) The number of good outcomes is $12$. The number of all outcomes is $12+88=100$ Hence the probability here is: $\frac{12}{100}$ b) The number of good outcomes is $12$. The number of all outcomes is $12+16=28$ Hence the probability here is: $\frac{12}{28}$ c) The number of good outcomes is $34$. The number of all outcomes is $88+34=122$ Hence the probability here is: $\frac{34}{122}$
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