Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-4 - Conditional Probability - Exercises - Page 44: 2-106

Answer

See below.

Work Step by Step

We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$ a) The number of good outcomes is $55+32=87$ The number of all outcomes is $55+32+17+3=107$ Hence the probability here is: $\frac{87}{107}$ b) The number of good outcomes is $55$ The number of all outcomes is $55+32=87$ Hence the probability here is: $\frac{55}{87}$ c) The number of good outcomes is $55$ The number of all outcomes is $55+17=72$ Hence the probability here is: $\frac{55}{72}$
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