Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-4 - Conditional Probability - Exercises - Page 44: 2-105

Answer

See below.

Work Step by Step

We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$ a) The number of good outcomes is $18$ The number of all outcomes is $14+18=32$ Hence the probability here is: $\frac{18}{32}$ b) The number of good outcomes is $14$ The number of all outcomes is $14+59=73$ Hence the probability here is: $\frac{14}{73}$ c) The number of good outcomes is $9$ The number of all outcomes is $9+18=27$ Hence the probability here is: $\frac{9}{27}$
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