Chapter 2 - Section 2-6 - Independence - Exercises - Page 53: 2-147

See below.

We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$ a) Hence $P(A)=\frac{22+8}{100}=0.3$, $P(B)=\frac{22+25+30}{100}=0.77$, $P(A\cap B)=\frac{22}{100}=0.22$. $P(A)P(B)=0.3\cdot0.77=0.231\ne0.22=P(A\cap B)$, thus they are not independent. b) $P(B|A)=\frac{P(A\cap B)}{P(A)}=\frac{0.22}{0.3}=0.733$