Answer
See below.
Work Step by Step
a) Here because the events are independent, $P=0.001\cdot0.001=0.000001$
b) Here because the events are independent, $P(data \ loss)=1-P(no\ failure)=1-(1-0.001)^2=0.001999$
Applied Statistics and Probability for Engineers, 6th Edition
by Montgomery, Douglas C.; Runger, George C.
Published by
Wiley
ISBN 10:
1118539710
ISBN 13:
978-1-11853-971-2
Chapter 2 - Section 2-6 - Independence - Exercises - Page 53: 2-148
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