Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 8 - Hypothesis Testing - 8-2 z Test for a Mean - Exercises 8-2 - Page 437: 21

Answer

The null hypothesis can not be rejected and this means that it can not be concluded that the average farm in Oregon differs from the national mean.

Work Step by Step

Given that, $\mu=444, \sigma=52, n=40, \bar x =430$, then, $H_{0}:\mu=444.\\ H_{1}:\mu \ne 444.$ $Z=\frac{\bar x- \mu}{\frac{\sigma}{\sqrt{n}}}=\frac{430- 444}{\frac{52}{\sqrt{40}}}\approx -1.70$ $P-value =2\times(1-P(Z\leq 1.70)=2\times(1-0.9554)=0.0892$ Since $\alpha=0.05$ and $P-value =0.0892$, the null hypothesis can not be rejected.
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