Answer
No, see explanations.
Work Step by Step
Step 1 State the hypotheses and identify the claim.
$H_0: \mu\geq546$
$H_1: \mu\lt546$ (claim, left-tailed test)
Step 2 Compute the test value.
Given $\bar X=544.8, \sigma=3, n=36$, we can calculate the test values as $Z=\frac{\bar X-\mu}{\sigma/\sqrt n}=\frac{544.8-546}{3/\sqrt {36}}=-2.4$
Step 3 Find the P-value.
With the above results and use a table or a calculator, we can find the corresponding P-value as $P=0.0224$
Step 4 Make the decision.
At $\alpha=0.01$, $P\gt\alpha$, we do not reject the null hypothesis.
Step 5 Summarize the results.
At $\alpha=0.01$, we do not have enough evidence to reject the null hypothesis.
It can not be concluded that the average number of calories burned is less than originally thought.
