Answer
No, see explanations.
Work Step by Step
Step 1 State the hypotheses and identify the claim.
$H_0: \mu\geq40$
$H_1: \mu\lt40$ (claim, left-tailed test)
Step 2 Compute the test value.
With the given data, we can find its mean as $\bar X=29.26$. Given $\sigma=30.9, n=50$, we can get the test values as $Z=\frac{\bar X-\mu}{\sigma/\sqrt n}=\frac{29.26-40}{30.9/\sqrt {50}}=-2.4577$
Step 3 Find the P-value.
With the above results and use a table or a calculator, we can find the corresponding P-value as $P=0.0195$
Step 4 Make the decision.
As $P\gt\alpha$, we do not reject the null hypothesis.
Step 5 Summarize the results.
At $\alpha=0.01$, we do not have enough evidence to support the claim that the average number of pages a person copies on the store’s copy machine is less than 40.
