Essentials of Statistics for the Behavioral Sciences 8th Edition

Published by Cengage Learning
ISBN 10: 1133956572
ISBN 13: 978-1-13395-657-0

Chapter 3 - Measures of Central Tendency - Problems - Page 85: 13

Answer

The new mean: $M=10$

Work Step by Step

$M=\frac{∑X}{N}$ There are 10 scores whose mean is $9$: $9=\frac{X_1+X_2+X_3+X_4+X_5+X_6+X_7+X_8+X_9+X_{10}}{10}$ $X_1+X_2+X_3+X_4+X_5+X_6+X_7+X_8+X_9+X_{10}=9\times10=90$ Now, remove a person with a score of $0$. Since the position of this score in the sum above makes no difference, let's name this score as $X_{10}$ $X_1+X_2+X_3+X_4+X_5+X_6+X_7+X_8+X_9+X_{10}=90$ $X_1+X_2+X_3+X_4+X_5+X_6+X_7+X_8+X_9+0=90$ $X_1+X_2+X_3+X_4+X_5+X_6+X_7+X_8+X_9=90$ Find the new mean: $M=\frac{∑X}{N}=\frac{X_1+X_2+X_3+X_4+X_5+X_6+X_7+X_8+X_9}{9}=\frac{90}{9}=10$
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