Answer
We will reject the Null Hypothesis at the 0.05 significance level in favor of the alternative hypothesis.
Work Step by Step
Here we have $H_{o}$: μ = 22, $H_{1}$: μ > 22, n = 200, x̅ = 22.6, s = 3.9 and α = 0.05
Using Classical approach:
Using Table VI, we have: t = 1.660
$σ_{ x̅} = \frac{s}{\sqrt n} = \frac{3.9}{\sqrt 200} = 0.276$
$t = \frac{22.6 - 22}{0.276} = 2.176$
Since, 2.176 > 1.660, we will reject the Null hypothesis.
