Answer
We reject the null hypothesis. Thus we have sufficient evidence to believe that the kidney weight of the offspring whose parents were exposed to 50 mg/L of para-nonylphenol in drinking water for 4 weeks is greater than the normal weight.
Work Step by Step
Here we have $H_{o}$: μ = 355.7 mg, $H_{a}$: μ > 355.7 mg, n = 12, x̅ = 396.9, s = 45.4 and α = 0.05
Using the classical approach:
Using Table VI, we have: t = 1.796
$σ_{ x̅} = \frac{s}{\sqrt n} = \frac{45.4}{\sqrt 12} = 13.106$
$t = \frac{396.9 - 355.7}{2.1} = 3.14$
Since, 3.14 > 1.796, we will reject the Null hypothesis.
