Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 12 - Section 12.1 - Assess Your Understanding - Applying the Concepts - Page 598: 27b

Answer

$X^2\lt X_α^2$: null hypothesis is not rejected. There is not enough evidence to conclude that mothers between the ages of 35 and 39 years give birth to a higher percentage of low-birth-weight babies.

Work Step by Step

$H_0:~p=0.071$ versus $H_1:~p\gt0.071$ Total: 240 births From item (a): $E(low~birth~weight~babies)=17.04$ $E(not~low~birth~weight~babies)=222.96$ Observed number of low birth weight babies: 22 Observed number of not low birth weight babies: $240-22=218$ $X^2=Σ\frac{(O_i-E_i)^2}{E_1}=\frac{(22-17.04)^2}{17.04}+\frac{(218-222.96)^2}{222.96}=1.55$ $k=2$. So, $d.f.=2-1=1$ $X_α^2=X_{0.05}^2=3.841$ (According to Table VII, for d.f. = 1 and area to the right of critical value = 0.05) Since $X^2\lt X_α^2$, we do not reject the null hypothesis.
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