Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 12 - Section 12.1 - Assess Your Understanding - Applying the Concepts - Page 598: 29d

Answer

$E(0)=226.7136$ $E(1)=211.3926$ $E(2)=98.5536$ $E(3)=30.6432$ $E(4~or~more~hits)=8.6976$

Work Step by Step

$P(0)=0.3936$ $P(1)=0.3670$ $P(2)=0.1711$ $P(3)=0.0532$ $P(4~or~more~hits)=0.0151$ Total: $n=576~rockets$. $E(0)=nP(0)=576\times0.3936=226.7136$ $E(1)=nP(1)=576\times0.3670=211.3926$ $E(2)=nP(2)=576\times0.1711=98.5536$ $E(3)=nP(3)=576\times0.0532=30.6432$ $E(4~or~more~hits)=nP(4~or~more~hits)=576\times0.0151=8.6976$
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